x=0
while x<20:
x+=1
y=x^x
print(y)
So the expected output to be 2,27,256,3125…………. But all it keeps showing is 0 0 0 0.
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2`^` is not the correct operator. use `**` – warped Feb 08 '21 at 06:43
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1^ is the xor operator. Anything xor-ed with itself is 0. So you are repeatedly setting y to 0. – Frank Yellin Feb 08 '21 at 06:44
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1Note, that when corrected, the output would be 1, 4, 27, ... Rather than 2, 27, 256, ... (not sure where your expected output came from). – costaparas Feb 08 '21 at 06:46
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as mentioned use `**`, `for x in [ (x+1) ** (x+1) for x in range(0, 20)]: print(x)` – D. Seah Feb 08 '21 at 06:48
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Dupe: https://stackoverflow.com/q/2451386/2988730 – Mad Physicist Feb 08 '21 at 06:48
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Another dupe: https://stackoverflow.com/q/48938847/2988730 – Mad Physicist Feb 08 '21 at 06:49
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1Also, your question should say something like "*I want print out `x`-squared using this loop*", not "*I want x to be incremented*". Please check out the [tour] and the [question guide](https://stackoverflow.com/help/how-to-ask) to help you write well-written questions in future. – costaparas Feb 08 '21 at 06:49
1 Answers
0
^ is bit-wise XOR.
Exponentiation is **
x=0
while x < 20:
x += 1
y = x ** x
print(y)
Prune
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