replicate the seq function in R to python

Question

I am trying replicate R's seq function in Python

For example in R:

sequence = seq(from = 1, to = 3, by = 1)
output = 1 2 3

And in Python I find the linspace commmand:

np.linspace(start=1, stop=3, num=1)
output = array([1.])

But it specifies the number of elements rather than the step size.

I was looking for something like R's output.

I understand that these kinds of questions would be duplicates almost always, but I would appreciate the community to be understanding of the following situation: people like me, learning Python after R tend to ask questions exactly like the OP "What is the equivalent of X function in Python?". These are legit and normal questions given that one learns how to navigate the help documentation and "philosophy" of a new language. I am not yet aware of a place where such questions would be fully welcomed without feeling that we saturate StackOverflow with duplicated questions. — Valentin_Ștefan, May 17 '22 at 06:40

score 1 · Answer 1 · answered Feb 08 '21 at 10:06

1

Note that num is not equivalent to by.

num: int, optional

Number of samples to generate. Default is 50. Must be non-negative.

Try with

>>> np.linspace(start=1, stop=3, num=3)
array([1., 2., 3.])

answered Feb 08 '21 at 10:06

so isnt there a replicate of by in python ? – pylearner Feb 08 '21 at 10:08
np.arange(11, 17, 0.5).tolist() – pylearner Feb 08 '21 at 10:10
@pylearner Well, `seq` equivalent is `np.linspace` but what I am saying is that `num` defines the number of samples you want to generate (in this case `3`) but in `seq`, `by` argument is actually the step. – Giorgos Myrianthous Feb 08 '21 at 10:11
oh i got it ... thanks @giorgos – pylearner Feb 08 '21 at 10:11

score 0 · Answer 2 · answered Feb 08 '21 at 10:06

0

[x for x in range(1, 4, 1)]
# [1, 2, 3]

answered Feb 08 '21 at 10:06

s_baldur

2 Answers2