Here is my code to solve for this equation manually:
b=2
c=3
sum= [[1, 4 + c, 0], [6, 2 + b + c, b]]
[[1, 7, 0], [6, 7, 2]]
this is the output I get and it works and the type : <class 'list'>
How do I get the same output but as a string? I don't want to change the above list type to string.
b=2
c=3
sum= "[[1, 4 + c, 0], [6, 2 + b + c, b]]"
'[[1, 4 + c, 0], [6, 2 + b + c, b]]'
Why does this not work, it is the right output "type" but the values for b and c don't work.
Thanks for your help.
You can use lambda or in other words use function def
NOTE: don't use sum as a variable name, because it is a built-in function in python.
b=2
c=3
sum_ = lambda b,c: [[1, 4 + c, 0], [6, 2 + b + c, b]]
sum_(b,c)
[[1, 7, 0], [6, 7, 2]]
This is pretty easy to do. You can use eval() to evaluate python expressions. From the documentation, for eval, the source may be a string representing a Python expression or a code object as returned by compile(). If I understood you correctly, you need to use for strings.
For example,
>>> b=2
>>> c=3
>>> sum= "[[1, 4 + c, 0], [6, 2 + b + c, b]]"
>>> result=eval(sum)
>>> result
[[1, 7, 0], [6, 7, 2]]
If you want to convert it to string, simply do result=str(eval(sum)).
What about:
sum = f"[[1, {4 + c}, 0], [6, {2 + b + c}, b]]"
Or this:
sum = str([[1, 4 + c, 0], [6, 2 + b + c, b]])
Or even this (not very recommended):
sum = eval("[[1, 4 + c, 0], [6, 2 + b + c, b]]")
