How to take Time Input in a line in Java?

Question

The problem is for Java

I want to take time input as follows

12:00 AM 11:42 PM

There will be a sequence of such inputs up to N lines.

Here two different Time Inputs are given

1)12:00 AM

2)11:42 PM

but they are in the same line.

The time inputs are for a single person entering(12:00 AM) and leaving(11:42 PM)

I know SimpleDateFormat but I can't modify it to suit my needs as said.

So please help

What if you take it in a single String and Split it based on Space Like Array = 12:00 | AM | 11:42 | PM And Consider InTime = Array[0] + Array[1] OutTime = Array[2] + Array[3] — Raj Raj, Feb 12 '21 at 11:32
Split the line at second space and than use SimpleDateFormat to parse each part. If you are still stuck, post your code and details about what still doesn't work. — MrSmith42, Feb 12 '21 at 11:35
I recommend you don’t use `SimpleDateFormat`. That class is notoriously troublesome and long outdated. Instead use `DateTimeFormatter` from [java.time, the modern Java date and time API](https://docs.oracle.com/javase/tutorial/datetime/). — Ole V.V., Feb 12 '21 at 14:42
Does this answer your question? [Extract multiple dates (dd-MMM-yyyy format) from a string in java](https://stackoverflow.com/questions/56848346/extract-multiple-dates-dd-mmm-yyyy-format-from-a-string-in-java) — Joe, Feb 14 '21 at 06:00

score 1 · Answer 1 · answered Feb 12 '21 at 11:50

This for the above problem , regular expression is very helpful to find and collect the value from input string/text. as given below.

public static void main(String[] args) {
        String input = "12:00 AM 11:42 PM";
        ArrayList<String> list = new ArrayList();
        Pattern pattern = Pattern.compile("[\\d:]*[ ](AM|PM)");
          //Matching the compiled pattern in the String
          Matcher matcher = pattern.matcher(input);
          while (matcher.find()) {
             list.add(matcher.group());
          }
          Iterator<String> it = list.iterator();
          System.out.println("List of matches: ");
          while(it.hasNext()){
             System.out.println(it.next());
          }
    }

here we have input string contains time. then we are using regex to find the pattern one the match found we are collecting that into list.

Thanks for the answer but I have never came across Pattern and Matcher datatypes — Manav Sarkar, Feb 14 '21 at 04:25

score 0 · Answer 2 · answered Feb 12 '21 at 11:38

There is lots of ways of doing this. I would use Regular Expression.

        String input = "12:00 AM 11:42 PM";
        String pattern = "(\\d+:\\d+ AM) (\\d+:\\d+ PM)";

        Pattern r = Pattern.compile(pattern);
        Matcher m = r.matcher(input);

        if(m.find()) {
            String am = m.group(1);
            String pm = m.group(2);

        }

This gives you two strings am and pm.

Then you can use SimpleDateFormat to parse them as Date.

SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm aa");

score 0 · Answer 3 · answered Feb 12 '21 at 11:41

0

The format you are looking for is: hh:mm a.

From JavaDoc:

Symbol	Desc	Type	Example
h	clock-hour-of-am-pm (1-12)	number	12
m	minute-of-hour	number	30
a	am-pm-of-day	text	PM

answered Feb 12 '21 at 11:41

Piotr W.

1
1
1

Thanks for contributing. It doesn’t really answer the question the way I understand it since there are two times on each line. – Ole V.V. Feb 12 '21 at 14:25

AKSingh · Answer 4 · 2021-02-12T13:52:39.840

As everyone said, regex is the best option. I will provide you with a simple method. I will use BufferedReader as an example here. Feel free to use any input stream.

BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

For n inputs simply accept n and start a loop.

int n = Integer.parseInt(bufferedReader.readLine().trim());
for (int i = 0;i < n;i++)

Each time you will accept each line of input consisting both date of arrival and departure as a single expression and split it using regex into 6 parts using delimiters : and whitespace. Eg: 12:00 AM 11:42 PM will be split into and array of Strings consisting of elements [12, 00, AM, 11, 42, PM].

String[] in = bufferedReader.readLine().split("[: ]");

//Array L to store HH MM XX of date of arrival at respective index
String[] L = new String[3];
L[0] = in[0];
L[1] = in[1];
L[2] = in[2];

//Array R to store HH MM XX of date of departure at respective index
String[] R = new String[3];
R[0] = in[3];
R[1] = in[4];
R[2] = in[5];

This approach will help you if want to perform any further calculations. You can also cast them to Integer using Integer wrapper class which will ease you in any type of arithmetic or comparative calculation. It is simple and straightforward, though a bit long.

I hope I have helped you.

score 0 · Answer 5 · answered Feb 12 '21 at 14:37

java.time and a regular expression

I recommend that you use java.time, the modern Java date and time API, for your time work. There are different ways to split the string into two to separate the two times in it; I too go for a regular expression. String.split() accepts one.

    DateTimeFormatter timeFormatter = DateTimeFormatter.ofPattern("h:mm a", Locale.ENGLISH);
    
    String inputLine = "12:00 AM 11:42 PM";
    String[] timeStrings = inputLine.split("(?<=M) ");
    if (timeStrings.length == 2) {
        LocalTime entering = LocalTime.parse(timeStrings[0], timeFormatter);
        LocalTime leaving = LocalTime.parse(timeStrings[1], timeFormatter);
        System.out.format("Entered %s, left %s.%n", entering, leaving);
    } else {
        System.err.println("Improper format: " + inputLine);
    }

Output from this snippet is:

Entered 00:00, left 23:42.

The regular expression (?<=M) matches a space preceded by an upper case M, so this is where the input string is being split.

Link: Oracle tutorial: Date Time explaining how to use java.time.

How to take Time Input in a line in Java?

5 Answers5

java.time and a regular expression