Convert string byte to byte like b'\x00\x01\x02'

Question

I have a string of bytes like this:

mystring = '000102'

And I need:

result = b'\x00\x01\x02'

Now I did:

# Opt 1
result = bytearray(mystring, 'utf-8') # I suppose is not correct encoded
# Opt 2
result  = mystring.encode()

And both give me, b'000102'. How can I obtain the '\x' that defines every byte?

Thank you very much, I suposes is an easy question, but I can't find how do it

[Python 3 - Hex-String to bytes - Stack Overflow](https://stackoverflow.com/questions/47996767/python-3-hex-string-to-bytes) ? — user202729, Feb 12 '21 at 12:40
Does this answer your question? [How to create python bytes object from long hex string?](https://stackoverflow.com/questions/443967/how-to-create-python-bytes-object-from-long-hex-string) — user202729, Feb 12 '21 at 12:41

kiranr · Accepted Answer · 2021-02-12T12:51:51.553

2

use bytes fromhex method

mystring = '000102'
y = bytes.fromhex(mystring)
print(y)

output:

b'\x00\x01\x02'

edited Feb 12 '21 at 12:51

answered Feb 12 '21 at 12:42

kiranr

score 0 · Answer 2 · answered Feb 12 '21 at 12:35

0

This should do it:

my_string = "012345"

result = b""

for i in range(len(my_string)//2):
    b += bytes(chr(int(my_string[i:i+1],16)),encoding="ASCII")

answered Feb 12 '21 at 12:35

Minek Po1

2 Answers2