I have following Post
, Category
& PostScore
Model.
class Post(models.Model):
category = models.ForeignKey('Category', on_delete=models.SET_NULL, related_name='category_posts', limit_choices_to={'parent_category': None}, blank=True, null=True)
status = models.CharField(max_length=100, choices=STATUS_CHOICES, default='draft')
deleted_at = models.DateTimeField(null=True, blank=True)
...
...
class Category(models.Model):
title = models.CharField(max_length=100)
parent_category = models.ForeignKey('self', on_delete=models.SET_NULL,
related_name='sub_categories', null=True, blank=True,
limit_choices_to={'parent_category': None})
...
...
class PostScore(models.Model):
post = models.OneToOneField(Post, on_delete=models.CASCADE, related_name='post_score')
total_score = models.DecimalField(max_digits=8, decimal_places=5, default=0)
...
...
So what i want is to write a query which returns N
number of posts (Posts) of each distinct category (Category) sorted by post score (denoted by total_score column in PostScore model) in descending manner. So that i have atmost N records of each category with highest post score.
So i can achieve the above mentioned thing by the following raw query which gives me top 10 posts having highest score of each category :
SELECT *
FROM (
SELECT *,
RANK() OVER (PARTITION BY "post"."category_id"
ORDER BY "postscore"."total_score" DESC) AS "rank"
FROM
"post"
LEFT OUTER JOIN
"postscore"
ON
("post"."id" = "postscore"."post_id")
WHERE
("post"."deleted_at" IS NULL AND "post"."status" = 'accepted')
ORDER BY
"postscore"."total_score"
DESC
) final_posts
WHERE
rank <= 10
What i have achieved so far using Django ORM:
>>> from django.db.models.expressions import Window
>>> from django.db.models.functions import Rank
>>> from django.db.models import F
>>> posts = Post.objects.annotate(
rank=Window( expression=Rank(),
order_by=F('post_score__total_score').desc(),
partition_by[F('category_id')]
)). \
filter(status='accepted', deleted_at__isnull=True). \
order_by('-post_score__total_score')
which roughly evaluates to
>>> print(posts.query)
>>> SELECT *,
RANK() OVER (PARTITION BY "post"."category_id"
ORDER BY "postscore"."total_score" DESC) AS "rank"
FROM
"post"
LEFT OUTER JOIN
"postscore"
ON
("post"."id" = "postscore"."post_id")
WHERE
("post"."deleted_at" IS NULL AND "post"."status" = 'accepted')
ORDER BY
"postscore"."total_score"
DESC
So basically what is missing that i need to limit each group (i.e category) results by using “rank” alias.
Would love to know how this can be done ?
I have seen one answer suggested by Alexandr on this question, one way of achieving this is by using Subquery and in operator . Although it satisfies the above condition and outputs the right results but the query is very slow.
Anyway this would be the query if I go by Alexandr suggestions:
>>> from django.db.models import OuterRef, Subquery
>>> q = Post.objects.filter(status='accepted', deleted_at__isnull=True,
category=OuterRef('category')).order_by('-post_score__total_score')[:10]
>>> posts = Post.objects.filter(id__in=Subquery(q.values('id')))
So i am more keen in completing the above raw query (which is almost done just misses the limit part) by using window function in ORM. Also, i think this can be achieved by using lateral join so answers in this direction are also welcomed.