Why is the last number getting logged as undefined in this for loop?

Asked Feb 13 '21 at 01:00

Active Feb 13 '21 at 01:12

Viewed 41 times

It always leaves the last element as undefined. Am I not incrementing correctly?

function loopASequenceAgain(start, end) {
  for (var i = start; i < end; i++) {
    console.log(i);
  }
}

console.log(loopASequenceAgain(2, 5));
// console output:
// 2
// 3
// 4
// 5

edited Feb 13 '21 at 01:04

Nick Parsons

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asked Feb 13 '21 at 01:00

rom feg

1

`loopASequenceAgain` doesn't return anything, so it will return undefined. So it should log undefined after all the numbers. This is expected – evolutionxbox Feb 13 '21 at 01:01
`loopASequenceAgain` doesn't return anything. `console.log(loopASequenceAgain(` doesn't make any sense – CertainPerformance Feb 13 '21 at 01:01
but im logging the element at the end of the for loop – rom feg Feb 13 '21 at 01:04
You don't even need the last `console.log`, You can just call the function and see the desired result. – Sushanth -- Feb 13 '21 at 01:04
And it isn't logging 5 because you used `<` instead of `<=` so the loop stops before it gets to that point. – John Montgomery Feb 13 '21 at 01:08

Why is the last number getting logged as undefined in this for loop?

0 Answers0