How to make try/except loop until true

Question

try:
    int(days)
except:
    print('Invalid input. A integer value was expected. Try again.')
    days = (input("Enter the number of days: ", ))

How do I make this try statement loop until true?

Answer 1

I suggest putting your logic in the try block, and ONLY printing the error message on exception:

while True:
    try:
        days = int(input("Enter the number of days: "))
        break
    except ValueError:
        print("Invalid input. An integer value was expected. Try again.")

Also, you should never use a bare except. It is generally considered bad practice.

Answer 2

Wrap it in a while loop like this:

while True:  # Don't exit until `break` is reached!
    days = input("Enter the number of days: ", )  # Move this here so `days` is always defined
    try:
        num_days = int(days)  # Save to a variable for later use
        break  # If the conversion succeeded, it will run this and exit the loop
    except ValueError:  # If the conversion failed (always specify a specific exception!), print the below:
        print('Invalid input. A integer value was expected. Try again.')

Answer 3

Make a while statement and a variable to end it after int(days):

days = int(input("Enter the number of days: "))
done = False
while done == False:
    try:
        int(days)
        done = True
    except:
        print('Invalid input. A integer value was expected. Try again.')
        days = (input("Enter the number of days: ", ))