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I'm trying to make a number guesser that starts from 000001 and counts up all the way to 999999 how can I do that?

ddejohn
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Jackson Long
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  • do you mean, "if i input a number, and an n, you want to print the output containing n digits?" – Tharun K Feb 20 '21 at 07:44
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    You can't do this with actual numbers like `int` or `float` but if you are able to use strings, then you can use string formatting to left-pad the numbers with a 0. – ddejohn Feb 20 '21 at 07:45

2 Answers2

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You can use str.format() like this:

num = 2
print("num: {0:03d}".format(num))

output:

num: 002
hata
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0

For dynamically choosing the pad-width:

>>> num_digits = 6
>>> f"{str(x).rjust(num_digits, '0')}"
'000003'
>>> num_digits = 3
>>> f"{str(x).rjust(num_digits, '0')}"
'003'
>>> x = 521
>>> f"{str(x).rjust(num_digits, '0')}"
'521'
ddejohn
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  • Seems you've edited your post, and now it's clear that dynamically choosing the pad-width is not what you need, so either use Hata's answer or slightly cleaner: `f"{x:>06}"` – ddejohn Feb 20 '21 at 08:14