How to convert float to without zeros and points

Question

I'm programming in C language and I'm in doubt with the conversion of floating values.

I have this summarized code that works perfectly:

float number = get_float("Number: ");
float convert= number * 100; 
printf("Number: %g\n", convert);

Using printf with %g I can see the number without the zeros and points.

Has I how to get the same result of printf with %g, but concatenating in the float convert variable and get the conversion directly ?

Output:

I have it:

0.70 ----> 70.000000

I need it:

0.70 ----> 70

Thank you

I don't understand the question. Can you show some examples of input and desired results? — Barmar, Feb 22 '21 at 17:08
Maybe you're looking for `sprintf()`, which is like `printf()` but puts the result in a string instead of printing it? — Barmar, Feb 22 '21 at 17:09
you mean [roundf](https://en.cppreference.com/w/c/numeric/math/round) ? — bolov, Feb 22 '21 at 17:21
You need to look into format specifiers, in your case `%.0f` — Jack Lilhammers, Feb 22 '21 at 17:21
You need to define it precisely. Do you want to round it as per arithmetic rules? Or you want to truncate it? Or something else? — Eugene Sh., Feb 22 '21 at 17:22
You wouldn't be doing monetary calculations with `float`, would you? [**Why not use Double or Float to represent currency?**](https://stackoverflow.com/questions/3730019/why-not-use-double-or-float-to-represent-currency) — Andrew Henle, Feb 22 '21 at 17:25
Anyway, this looks like a part of some currency related CS50 exercise. In such a case using `floats` is a bad idea in general. Use integers for dollars and integers for cents. — Eugene Sh., Feb 22 '21 at 17:25

score 2 · Answer 1 · answered Feb 22 '21 at 17:22

2

Read the documentation of print and specifier %f

printf("Number: %.0f\n", convert);
// print floating point with no point and 0
// eg : printf("Number: %.0f\n", 70.0000); -> 70

answered Feb 22 '21 at 17:22

Ptit Xav

3,006
2
6
15

score 1 · Accepted Answer · answered Feb 22 '21 at 17:22

1

What you need is a int. int does not have a decimal part. Try this

int convert= number * 100;

answered Feb 22 '21 at 17:22

zeitgeist

852
12
19

score 0 · Answer 3 · answered Feb 22 '21 at 17:31

Casting should do the trick. Here is modified version of ur code which works as required:

#include <stdio.h>
#include <stdlib.h>

int main()
{
  // getting float
  float number = get_float("Number: ");

  // casting to int to get rid of fractional part
  int convert = (int)(number * 100);

  // printing to check
  printf("Number: %d\n", convert);
  
  return (0);
}

How to convert float to without zeros and points

3 Answers3