Print exact min value of a list

Question

I am trying to print the exact minimum value from a list using the sample code below:

mylist = [value]

while True:
    price_list.append(value)
    low_value = min(value)
    print("min value = " float(low_value))


    time.sleep(600)

value is being constantly updated from my website scraper pulling data from my website. Often the actual value displayed is 19.9900, however, the output is "min value = 19.9" or "min value = 19" depending on the price change.

I would like the full value to be displayed (eg. 19.9900) and I am having trouble doing this.

Then it's the problem with your scraper function. Please add the code for that. — abhigyanj, Feb 23 '21 at 01:16
Does this answer your question? [Force python to print a certain number of decimal places](https://stackoverflow.com/questions/56217081/force-python-to-print-a-certain-number-of-decimal-places) — theProcrastinator, Feb 23 '21 at 02:18

theProcrastinator · Answer 1 · 2021-02-23T01:26:58.390

0

Try something like:

print(f"{low_value:.6f}")

You can check out this answer too for more details.

edited Feb 23 '21 at 01:26

answered Feb 23 '21 at 01:18

theProcrastinator

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I tried this too. It didn't do the trick. – Brendan Feb 23 '21 at 01:23
3

Thats because this code will cause a syntax error. @Brendan Try using `print(f"{low_value:.6f}")` instead. – PacketLoss Feb 23 '21 at 01:24
Thanks @PacketLoss I missed out on the colon. Included it now:) – theProcrastinator Feb 23 '21 at 01:27

Print exact min value of a list

1 Answers1