How to print byte array in hexadecimal - c++

Question

I have a piece of code here:

#include <iostream>
#include <iomanip>
using namespace std;

int main(void)
{
  
  
  unsigned char bytes[] = {0x43,0x4d,0x30,0x30,0x0f,0x0D};
  
  std::cout << std::hex << bytes[0] <<std::endl;
  

}

The above program is printing C to command line. How can I make the program to print 43 to commandline. My OS is Windows 10, 64 bit.

Any `char` value printed with `<<` will be printed as a character. You need to convert the value to a non-`char` integer type. For example `int`. — Some programmer dude, Feb 25 '21 at 04:42
Unless you need to pass your array on to a function that needs an array of bytes (or shorts) there's really no use in using smaller integer types. Use `int` (or `unsigned`) instead. — Some programmer dude, Feb 25 '21 at 04:44

score 1 · Accepted Answer · answered Feb 25 '21 at 04:45

1

Use printf function:

#include<cstdio>
...
printf("%x", bytes[0]);

See here if you want to know more about printf function.

answered Feb 25 '21 at 04:45

robbinc91

548
6
14

@RetiredNinja static_cast(bytes[0]) also works. – Vinod Feb 25 '21 at 05:15
(int)(bytes[0]) works too. – robbinc91 Feb 25 '21 at 14:12

How to print byte array in hexadecimal - c++

1 Answers1