Int to ASCII char and char to ASCII number | C++

Question

I must write short script which will change int to ASCII char and char to ASCII int. But i don't know how. I wrote this short code but something is wrong. I'm programming for half-year. Can someone write it working? It is my first time to use functions in c++

#include <iostream>
#include <conio.h>

using namespace std;
char toChar(int n) {
return n + '0';
}
int toInt(char c) {
return c - '0';
}
int main()
{
int number;
cout << "Int: ";
cin >> number;
cout << "ASCII: " << static_cast<char>(number);
getch();
return 0;
}

What exactly is wrong? What's the current output and what is the expected output? How are you running the program (which number you give it as input)? See also [example]. — user202729, Feb 26 '21 at 14:15
Suppose you have `int x = 1;` you can then interpret that as ascii `1`, or you can get the ascii code for the character `'1'`. To be sure what you want you should include input, output and expected output — 463035818_is_not_an_ai, Feb 26 '21 at 14:18
If you have an error with `_getch` don't use `_getch`! Use `getch` instead — Dock, Feb 26 '21 at 14:27
i edited it but i don't know how to use this functions toChar and toInt — Kacper Podsiadło, Feb 26 '21 at 14:45
maybe someone can write it working? it is my first time to use functions in c++ — Kacper Podsiadło, Feb 26 '21 at 14:51

score 1 · Answer 1 · answered Feb 26 '21 at 15:50

1

Thank You very much Guys, I have done it with shorter and working code.

#include <iostream>
using namespace std;
int main(){
int a=68;
cout<<char(a);
char c='D';
cout<<int(c);
return 0;
}

answered Feb 26 '21 at 15:50

Kacper Podsiadło

13
3

Antonin GAVREL · Answer 2 · 2021-02-26T15:23:15.523

0

#include <iostream>

using namespace std;

char toChar(int n)
{
    if (n > 127 || n < 0)
        return 0;
    return (char)n;
}

int toInt(char c)
{
    return (int)c;
}

int main()
{
    int number = 97;
    cout << "char corresponding to number " << number << " is '" <<  toChar(number) << "'\n";

    char car='H';
    cout << "number corresponding to char '" << car << "' is " << toInt(car) << "\n";

    return 0;
}

output:

char corresponding to number 97 is 'a'
number corresponding to char 'H' is 72'

Originally I thought you were just looking to convert the number: You can simply add and substract '0', to char and from char:

char toChar(int n) {
    return n + '0';
}

int toInt(char c) {
    return c - '0';
}

If you just want to cast the type, read this

edited Feb 26 '21 at 15:23

answered Feb 26 '21 at 14:17

Antonin GAVREL

9,682
8
54
81

where should i add this? – Kacper Podsiadło Feb 26 '21 at 14:21
above the main function – Antonin GAVREL Feb 26 '21 at 14:23
@KacperPodsiadło • why did you put `_getch` in the code in the first place? – Eljay Feb 26 '21 at 14:31
@KacperPodsiadło if you get the error for `_getch` after adding thsoe two function it should have been there already before. You should have explained in your question what is wrong and include the error message. – 463035818_is_not_an_ai Feb 26 '21 at 14:31
@AntoninGAVREL i still don't know what to do, can you write it but working or help one more time? – Kacper Podsiadło Feb 26 '21 at 14:58

Pat. ANDRIA · Answer 3 · 2021-02-26T15:15:30.067

May be you could start with the code below. If this is incomplete, could you please complete your question with test cases?

#include <iostream>


using namespace std;

char toChar(int n)
{   //you should test here the number shall be ranging from 0 to 127
    return (char)n;
}

int toInt(char c)
{
    return (int)c;
}

int main()
{
    int number = 97;
    cout << "number to ascii corresponding to  " << number << " is " <<(char)number << " or " << toChar(number) <<endl;

    char car='H';
    cout << "ascii to number corresponding to " << car << " is " << (int)car << " or " << toInt(car) << endl;

    return 0;
}

The output is:

number to ascii corresponding to  97 is a or a
ascii to number corresponding to H is 72 or 72

score 0 · Accepted Answer · answered Feb 26 '21 at 15:21

you could also use printf, so you don't need to create other function for converting the number.

int i = 64;
char c = 'a';

printf("number to ascii corresponding to %d is %c\n", i, i);
printf("ascii to number corresponding to %c is %d\n", c, c);

the output is gonna be

number to ascii corresponding to 64 is A
ascii to number corresponding to a is 97

Int to ASCII char and char to ASCII number | C++

4 Answers4