How to extract data FROM URL between slashes [PHP]

Question

I have

{$input = 'https://www.youtube.com/watch?v=JCA2PjAHmNw&list=RDGMEM_v2KDBP3d4f8uT-ilrs8fQVMXJu6RlDf2O4&index=7'}

Wanna to get JCA2PjAHmNw

I've just tried this:

{$input = 'https://www.youtube.com/watch?v=JCA2PjAHmNw&list=RDGMEM_v2KDBP3d4f8uT-ilrs8fQVMXJu6RlDf2O4&index=7'}
{$r = preg_match_all('#/mk_([^/]*)#', $input, $matches)}
{print_r($matches[0])}

But nothing happening

You can look at this post to get url parameters https://stackoverflow.com/questions/11480763/how-to-get-parameters-from-a-url-string — The fourth bird, Feb 27 '21 at 12:24

score 1 · Answer 1 · answered Feb 27 '21 at 12:32

1

Answer:

{$url='https://www.youtube.com/watch?v=KGseLn0zSI4&list=RDGMEM_v2KDBP3d4f8uT-ilrs8fQVMXJu6RlDf2O4&index=9'}
{$parts = parse_url($url)}
{parse_str($parts['query'], $query)}
{$query['v']}

answered Feb 27 '21 at 12:32

Valerius Romulus

55
8

score 1 · Answer 2 · answered Feb 27 '21 at 12:58

1

Use this regex:

$data = 'https://www.youtube.com/watch?v=JCA2PjAHmNw&list=RDGMEM_v2KDBP3d4f8uT-ilrs8fQVMXJu6RlDf2O4&index=7';
preg_match_all('~\?v=(.*)&~isU', $data, $return);
print_r($return[1][0]);

answered Feb 27 '21 at 12:58

No NAME

159
1
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How to extract data FROM URL between slashes [PHP]

2 Answers2