Why cant i call session start inside a function?

Asked Mar 01 '21 at 20:33

Active Mar 01 '21 at 21:16

Viewed 30 times

In the begging, on the console appears:

Uncaught SyntaxError: Unexpected token '<'" .

Can't i call this function or other functions? I would like to do somethings like insert on my SQL database but that minimal code there is struggling too and I don't know why (PHP funcion add).

<button type="button" onclick="phpadd()" onclick="showSwal('auto-close')" id="add" class="btn btn-lg clear font-weight-light" style="background-color: #fccf03;color: white;">Add to Log</button>
<?php
function add($a,$b){
  session_start();
  include('conexao.php');
  if (!$_SESSION['usuario']) {
    header('Location: indexM.php');
    exit();
  }
  return 1;
}
?>
<script>
function phpadd() {
  var padd = <?php echo add(1, 2); ?>; // call function to insert value
  alert(padd);
}
</script>

edited Mar 01 '21 at 21:16

Alessio Cantarella

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asked Mar 01 '21 at 20:33

Muax

2

Please post your code as plain text, not a screenshot – Barmar Mar 01 '21 at 20:36
You need to call `session_start()` before you've sent any output. You're sending the ` – Barmar Mar 01 '21 at 20:38
This also looks suspiciously like [What is the difference between client-side and server-side programming?](//stackoverflow.com/q/13840429) is worth reading next. – mario Mar 01 '21 at 20:41
@Barmar is done. – Muax Mar 01 '21 at 21:11
@Barmar if i remove that , it will appear the same error – Muax Mar 01 '21 at 21:12
@mario No, it's printing a session variable, not a post parameter, it seems OK. – Barmar Mar 01 '21 at 21:12
You probably have other output before that. The warning message tells you the first place where output began. – Barmar Mar 01 '21 at 21:13
You have to put `session_start()` before anything that produces output. – Barmar Mar 01 '21 at 21:14
@Barmar the error says it is here var padd = ; – Muax Mar 01 '21 at 21:15
On browser it appears like this var padd =
– Muax Mar 01 '21 at 21:16
Just put `session_start()` at the very beginning of the script, before anything else. – Barmar Mar 01 '21 at 21:17
I have that ,how can i send the whole code? – Muax Mar 01 '21 at 21:20
The problem is the include i dont know why – Muax Mar 01 '21 at 21:21
i have a previous include at the beggining and that php file calls the same include('conexao.php') cant it be the problem? – Muax Mar 01 '21 at 21:22

Why cant i call session start inside a function?

0 Answers0