As detailed, this line:
(! + [] + [] + ![])
Gives as result the string "truefalse"
I've been experimenting with it, but cannot fully grasp the implicit conversions happening, would like to know the reason behind the result.
Just curiosity.
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https://dev.to/tpenguinltg/comment/d2mf – dcangulo Mar 02 '21 at 04:48
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Here is something to confuse those who didn't go deep enough: `Array.prototype.join = () => 1; (! + [] + [] + ![]);` – ASDFGerte Mar 02 '21 at 04:58
1 Answers
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false => ![]
true => !![]
undefined => [][[]]
NaN => +[![]]
0 => +[]
1 => +!+[]
2 => !+[]+!+[]
10 => [+!+[]]+[+[]]
Array => []
Number => +[]
String => []+[]
Boolean => ![]
Function => []["filter"]
eval => []["filter"]["constructor"]( CODE )()
window => []["filter"]["constructor"]("return this")()
You can find more about it at http://www.jsfuck.com/ .
Hacky
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