Python Function: I am trying to take a two numbers and return True if either one of the parameters is even And both of them are less than 9

Question

def is_either_even_and_less_than_9(num1, num2):
    if (num1 and num2) > 9:
        return False
    if (num1 or num2) % 2 == 0:
        return True
    else:
        return False

I see you're a new contributor. I think the problem here is simply a small mistake regarding boolean logic and python syntax. It is, however, good practice in Stack Overflow to search for some similar questions before asking one yourself! It may sound mean, but consider breaking your problem into smaller problems, which in turn probably have a question regarding them! Hope you enjoy the community. — eduardokapp, Mar 03 '21 at 03:00

CryptoFool · Answer 1 · 2021-03-03T03:37:21.773

1

Your boolean logic syntax is wrong. You want:

def is_either_even_and_less_than_9(num1, num2):
    if num1 >= 9 and num2 >= 9:
        return False
    if num1 % 2  == 0 or num2 % 2 == 0:
        return True
    else:
        return False

edited Mar 03 '21 at 03:37

answered Mar 03 '21 at 02:57

CryptoFool

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score 0 · Accepted Answer · answered Mar 03 '21 at 03:02

num1 and/or num2 will return num2 which is then compared.

It should be:

def is_either_even_and_less_than_9(num1, num2):
    if num1 > 9 or num2 > 9:
        return False

    elif num1 % 2 == 0 or num2 % 2 == 0:
        return True

    else:
        return False

Python Function: I am trying to take a two numbers and return True if either one of the parameters is even And both of them are less than 9

2 Answers2