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I got a list of lists b and I want to check if they exist in list a which is also a list of lists.

I'm currently using the following method which is quite time-consuming. Is there a faster way?

b  = [[5], [5, 3], [5, 3, 1], [5, 3, 1, 2]] 
a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

result = all(elem in b[0] for elem in a[0])
print(result)
result = all(elem in b[1] for elem in a[0])
print(result)
result = all(elem in b[2] for elem in a[0])
print(result)
result = all(elem in b[3] for elem in a[0])
print(result)

result = all(elem in b[0] for elem in a[1])
print(result)
result = all(elem in b[1] for elem in a[1])
print(result)
result = all(elem in b[2] for elem in a[1])
print(result)
result = all(elem in b[3] for elem in a[1])
print(result) 

result = all(elem in b[0] for elem in a[2])
print(result)
result = all(elem in b[1] for elem in a[2])
print(result)
result = all(elem in b[2] for elem in a[2])
print(result)
result = all(elem in b[3] for elem in a[2])
print(result) 

Output:

>>>False
>>>False
>>>False
>>>True
>>>False
>>>False
>>>False
>>>False
>>>False
>>>False
>>>False
>>>False
Poornaka
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2 Answers2

0

You do the same thing with a double loop O(n^2):

for i in range(len(a)):
    for j in range(len(b)):
        print(all(elem in a[i] for elem in b[j]))
Allan Wind
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0
for i in range(len(b)):
   if b[i] in a:
      return True
   else:
      return False
throwaway
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