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I'm getting this error

No mapping found for HTTP request with URI [/val/valsys/auth/login] in DispatcherServlet with name 'val'

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>val</display-name>

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
     <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
</filter-mapping>


<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
    /WEB-INF/spring-security.xml
    /WEB-INF/applicationContext.xml 
    /WEB-INF/dwr-context.xml    
    </param-value>
</context-param>

<context-param>
    <param-name>log4jConfigLocation</param-name>
    <param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>

<context-param>
    <param-name>log4jRefreshInterval</param-name>
    <param-value>1000</param-value>
</context-param>


<servlet>
  <servlet-name>val</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
  <servlet-name>val</servlet-name>
  <url-pattern>/*</url-pattern>
</servlet-mapping>

 <servlet-mapping>
  <servlet-name>val</servlet-name>
  <url-pattern>/valsys/dwr/*</url-pattern>
</servlet-mapping>

<listener>
  <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<listener>
 <listener-class>org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>

<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
    </welcome-file-list> 
</web-app>

This is how my dispatcher.xml look like..

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p" 
xsi:schemaLocation="http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

<!-- Declare a view resolver -->
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" 
        p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" />

</beans>
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bala
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2 Answers2

1

Your mapping your request to the dispatcher servlet but you don't have any mapping defined in your dispatcher so it cannot handle it

Have a look at this simple example

objects
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  • i have a @controller in my project @Controller @RequestMapping("/auth") public class LoginLogoutController { @Resource(name="sessionRegistry") private SessionRegistryImpl sessionRegistry; @RequestMapping(value = "/login", method = RequestMethod.GET) public String getLoginPage() { System.out.println("in the login page controller"); return "login"; } and INFO efaultAnnotationHandlerMapping - Mapped URL path [/auth/login] onto handler [org.delegate.LoginLogoutController@7c16ee] in my console....please reply – bala Jul 11 '11 at 05:57
0

In 'WEB-INF/web.xml', we declare Spring DispatcherServlet and map '*.html' URLs to it:

lokeshmurge
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