I have the following array of objects:
Update: full code
export const fetchInvoices = function (firestore, currentUser) {
const db = firestore
.collection("customers")
.doc(currentUser)
.collection("subscriptions");
let invoices = [];
db.get().then((subscriptionSnapshot) => {
subscriptionSnapshot.forEach((doc) => {
doc.ref.collection("invoices").get().then((invoiceSnapshot) => {
invoiceSnapshot.forEach(async (doc) => {
let invoice = {
"billing_reason": doc.data().billing_reason,
"created": doc.data().created,
"currency": doc.data().currency,
"hosted_invoice_url": doc.data().hosted_invoice_url,
"id": doc.id,
"invoice_pdf": doc.data().invoice_pdf,
"number": doc.data().number,
"period_end": doc.data().period_end,
"period_start": doc.data().period_start,
"status": doc.data().status,
"subtotal": doc.data().subtotal,
"total": doc.data().total
};
Object.defineProperty(invoice, 'invoice_id', { value: doc.id });
invoices.push(invoice);
})
})
});
});
const sortedData = invoices.sort((a, b) => +(b.status === 'open') - +(a.status === 'open'));
console.log(sortedData);
return sortedData;
}
I want to sort them by the ones with status: "open" on the first indexes, and then sort by created. Is there a way to do this?
I've been trying to sort only the group of status: "open" using Object.values(obj).includes("open") to determine if the object has the value and then sort by truth as here.
But still can't even make this "sort by group".
