How to define the `path` attribute for a module in python 3?

Asked Mar 06 '21 at 18:36

Active Mar 06 '21 at 18:36

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TL;DR

I want to create a package (in fact, a package and sub-packages) in python3.

From python3 docs

packages are just a special kind of module. Specifically, any module that contains a __path__ attribute is considered a package.

My question is, where and how do I define the __path__ attribute?

My problem

I have the following directory/file structure in a python3 setup.

root_dir
├── migrate
    └── lib
        ├── __init__.py
        ├── database.py
        └── migrate.py

How do I turn migrate directory into a package, to be able to run

python -m migrate.lib.migrate

from inside the root_dir. I know that adding an __init__.py inside migrate directory will suffice to execute the above. But I wish to know understand more about the __path__ attribute.

asked Mar 06 '21 at 18:36

satvik.t

You should never need to set `__path__` yourself. – user2357112 Mar 06 '21 at 18:40
@user2357112supportsMonica Does that mean that the only way to turn a directory into a package in python2/3 is to add a `__init__.py` inside it? – satvik.t Mar 06 '21 at 18:45
Also, does adding `__init__.py` modify the `__path__` attribute? – satvik.t Mar 06 '21 at 18:46
https://stackoverflow.com/questions/2699287/what-is-path-useful-for what-is-path-useful-for – pippo1980 Mar 06 '21 at 19:04

How to define the `__path__` attribute for a module in python 3?

0 Answers0

How to define the `path` attribute for a module in python 3?