Question on how to work with class instances inside an array

Question

So i am learning how to work with classes and class instances and have created a scenario where i have a class Employee that is extended by three other classes that represent employees from different departments. I already managed to create a function that allows me to create a new instance of any class and push it into an array containing all existing employees.

So now i am trying to play around and iterate over the array and create new functions that allow me to access a specific value of any instance.

for example the first one i am trying to do is a function that return true or false if an employee is working remotely:

function areTheyRemote(employee){
    if (employee.workplace === 'home'){
        return true;
    } else {
        return false;
    }
}

I have no idea and couldn't find any answers online on how to do it, hoping you could shed a light on me. Cheers

Welcome to Stack Overflow! I'm afraid it's really not clear what precisely you're asking. Please take the [tour] (you get a badge!), have a look around, and read through the [help], in particular [*How do I ask a good question?*](/help/how-to-ask) I also recommend Jon Skeet's [Writing the Perfect Question](https://codeblog.jonskeet.uk/2010/08/29/writing-the-perfect-question/) and [Question Checklist](https://codeblog.jonskeet.uk/2012/11/24/stack-overflow-question-checklist/). — T.J. Crowder, Mar 09 '21 at 10:27
Side note: Nine parameters is **way** too many parameters for a function, trying to use it you'll get lost, even with IDE help. You might consider accepting an object with named properties (perhaps with destructuring), see the answers to [this question](https://stackoverflow.com/questions/11796093/is-there-a-way-to-provide-named-parameters-in-a-function-call-in-javascript). — T.J. Crowder, Mar 09 '21 at 10:29
i dont get it, why `employeeName = new team` (name vs team?) — Dee, Mar 09 '21 at 10:30
Something like `let employees = []; class Employee{ constructor(args){ console.log(args) } }; employees.push( new Employee({name:"...", age : 25}))` — Jeremy Thille, Mar 09 '21 at 10:34
Ah, you completely changed your question while I was typing my comment..... So, new comment : `I have no idea and couldn't find any answers online on how to do it`, why are you saying that, because that's exactly what `areTheyRemote()` is doing (also it could be written `const areTheyRemote = employee => !!employee.workplace==="home"`) — Jeremy Thille, Mar 09 '21 at 10:38
By changing the function argument to Employee i managed to do exactly what i needed and. also thank you for the comments on the previous function i showed on my question, changed it to make it simpler and more readable. — carneiro_squared, Mar 09 '21 at 11:28

David · Accepted Answer · 2021-03-09T10:51:01.777

1

Without seeing your class code for the employee it should be something like this:

function Employee(name, age, workplace) {
  this.name = name
  this.age = age
  this.workplace = workplace
}

const bob = new Employee('bob', 22, 'remote')

function areTheyRemote(employee) {
  if (employee.workplace === 'remote') {
    return true;
  } else {
    return false;
  }
}

console.log(areTheyRemote(bob))

edited Mar 09 '21 at 10:51

answered Mar 09 '21 at 10:35

David

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score 0 · Answer 2 · answered Mar 09 '21 at 11:32

After some more digging i found that my major error was not passing as argument the class. I capitalized "employee" as class syntax and it now runs as intended.

Also simplified the previous function to create new class instances, so thank you for the comments.

Question on how to work with class instances inside an array

2 Answers2