How to cross check if random numbers are the same

Question

I am trying to make a very simple poker game in Python. Let's say I for example generate six random numbers by simply using the randint function. Would it be possible to cross-check all the numbers that get generated? An example of code could be this:

dice1=randint(1,6)
dice2=randint(1,6)
dice3=randint(1,6)
dice4=randint(1,6)
dice5=randint(1,6)
dice6=randint(1,6)

I know that I can do something along the lines of this to check if they are equal to eachother or not:

if dice1==dice2 && dice2==dice3 && dice3==dice4 && dice4==dice5 && dice5==dice6:
/////whatever function

The question is if it is possible to check if I can check if dice1==dice6 in a short and easy way, while also checking all the other dice their similarities or differences.

You'd be much better off putting those dice in a list and then doing `if all(dices[0] == dice for dice in dices)` — Tomerikoo, Mar 09 '21 at 16:02
By the way, in Python you probably want `and` instead of that `&&` — Tomerikoo, Mar 09 '21 at 16:03
But how would I be able to check if, for example, dice2 is the same as dice5? — Beaver, Mar 09 '21 at 16:04

score 1 · Answer 1 · answered Mar 09 '21 at 16:03

1

Use a list of dice instead of 6 variables, then you can do:

dice = [randint(1,6) for _ in range(6)]
print(all(die == dice[0] for die in dice))

answered Mar 09 '21 at 16:03

SuperStormer

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Would it be possible to print the 6 random numbers? – Beaver Mar 09 '21 at 16:17
@Beaver `print(dice)`... – Tomerikoo Mar 09 '21 at 16:19
@Tomerikoo would it be possible to print something else than "False" – Beaver Mar 09 '21 at 16:21
@Beaver Your question(s) are really not clear. Please edit your question with a clear problem statement. Usually sample inputs and expected outputs help best to describe your problem. You can read about [ask] and how to provide a [mre] for more advice – Tomerikoo Mar 09 '21 at 16:24

score 0 · Answer 2 · answered Mar 09 '21 at 16:03

0

If you only want to check if dice1 and dice6 are equal, you can just use the expression dice1 == dice6. If you want to check all of the elements, though, you can try this:

dice = [dice1, dice2, dice3, ... dice6]
if all([dice[0] == d for d in dice]):
    # Do something here

However, this method would not allow you to check which die does not equal the others.

answered Mar 09 '21 at 16:03

Jacob Lee

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I want to be able to check all the variables and see if they match or not at once. If I wouldn't be able to check whether the die is equal to others this wouldn't be of any help right? – Beaver Mar 09 '21 at 16:16
@Beaver Can you clarify your question please? You haven't really said clearly what it is you're trying to do. Do you want to check if ***all*** dies are the same? – Tomerikoo Mar 09 '21 at 16:17
I indeed want to check all the die at the same time and be able to print all the generated numbers. So for example, you get a 5, 4, 2, 2, 6, 2, it would print those numbers, and tell how many numbers are equal – Beaver Mar 09 '21 at 16:19
@Beaver That's not, in any way, understandable from the question itself... – Tomerikoo Mar 09 '21 at 17:08

Mark Ransom · Answer 3 · 2021-03-09T16:10:26.390

0

The quickest way is to create a set, because sets don't allow duplicates.

if len(set([dice1, dice2, dice3, dice4, dice5, dice6])) != 6:  # there are duplicates

edited Mar 09 '21 at 16:10

answered Mar 09 '21 at 16:04

Mark Ransom

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When using this i get the following error: `TypeError: set expected at most 1 arguments, got 6` – Beaver Mar 09 '21 at 16:09
@Beaver sorry, I thought that would work. Just put `[` and `]` around the parameters to turn them into a list. I've edited the answer. – Mark Ransom Mar 09 '21 at 16:10
This works, thank you! – Beaver Mar 09 '21 at 16:14

How to cross check if random numbers are the same

3 Answers3