I need to print without comma in last position

Question

n = int(input("Enter a number :-"))
for i in range(1, 11):
    print(i*n, end = ",")

When I tried this program, in output I have got a comma in the last position. But I don't want this comma. How can I remove the comma? I just code it for a multiplication table.

Output: 8,16,24,32,40,48,56,64,72,80,

Answer 1

You can check the index before printing

n = int(input("Enter a number :-"))
for i in range(1, 11):
    end = "," if i < 10 else ""
    print(i*n, end = end)

Answer 2

Python lets you do this easily with join:

n = int(input("Enter a number: "))
print(','.join(str(i*n) for i in range(1, n)))  # surely, range(1, n) not range(1, 11)

For more complex situations, a common solution is to prefix each item except the first.

n = int(input("Enter a number: "))
sep = ""
for i in range(1, n):  # same fix here
    print("%s%i" % (sep, i*n), end = "")
    sep = ","   # add a delimiter on each subsequent iteration

Answer 3

Produce a series which you pass into print all at once with a custom separator, instead of requiring to figure out the correct end-of-line in separate print calls:

print(*(i*n for i in range(1, 11)), sep=',')

This * unpacks the generator (i*n for i in range(1, 11)) as arguments to print, in essence being equivalent to:

print(8, 16, 24, ..., sep=',')

Answer 4

the best way to do this is using Join function

using Using generator expression:

def gen_num(n,count):
    for i in range(1, count):
        yield str(i*n)

print(",".join(list(gen_num(8,11))))

using list comprehension

n = 8
print(",".join([str(x*n) for x in range(1,11)]))

Result: 8,16,24,32,40,48,56,64,72,80