Reg ex for deleting digits and the parenthesis on python

Question

I'm filtering and cleaning some data such as this one(東急オリジナルお礼品(18)). I tried the following to filter out the digits and the parenthesis. Case 1 categoryData = re.sub(r"\(.*?\)", "", category_element.find("span").get_text())

Case 2 categoryData = re.sub(r"/\([0-9]+\)/", "", category_element.find("span").get_text())

Still it is not working

My goal is tho have this data only(東急オリジナルお礼品)

It should be `r"\([0-9]+\)"` – anubhava Mar 10 '21 at 06:51 — anubhava, Mar 10 '21 at 06:51
Hi!. I tried it. Still the same issue – Ariel Anasco Mar 10 '21 at 06:53 — Ariel Anasco, Mar 10 '21 at 06:53

score 1 · Accepted Answer · answered Mar 10 '21 at 10:15

1

import re

match = r"\([0-9]+\)"
string = "東急オリジナルお礼品(18)"
self.categoryData = re.sub(match, '', string)

Result:

東急オリジナルお礼品

answered Mar 10 '21 at 10:15

Diego Miguel

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13

I would go more in this direction with pattern: `match = r"([^\w\s]+|\d+)"` - `\w` is alpha-numeric, compliant with any alphabet - so just remove digits and you have everything that is neither letter in any alphabet, nor space (you might add punctuation - OP wasn't clear about that). – Grzegorz Skibinski Mar 18 '21 at 16:13

Reg ex for deleting digits and the parenthesis on python

1 Answers1