Print random integer and phrase in same line?

Question

Not sure if this is asked before but: How do you print "searching for x" where "x" is a random integer? I have my code below:

from random import randint

numbers = []
random = randint(1,50)

for i in range(0,10):
  numbers.append(randint(1,50))

for j in range(len(numbers)):
  print('searching for')
  print(random)
  print('in')
  print(numbers)
  break

And this is what happens but I want "searching for __ in [list]" on the same line. Is there a way to do it?

Thanks in advance!

Aside from the linked duplicates, what happened when you typed `python print on same line` into a search engine? — Karl Knechtel, Mar 14 '21 at 20:55

score 0 · Accepted Answer · answered Mar 14 '21 at 20:54

0

try this:

print(f'searching for {random} in {numbers}')

it requires python 3.6 or up and it is called an f-string

answered Mar 14 '21 at 20:54

Mirronelli

740
5
14

score 0 · Answer 2 · answered Mar 14 '21 at 20:54

0

for n in numbers:
  print("Searching for {} in {}".format(n, numbers))

Does that answer what you want to do?

answered Mar 14 '21 at 20:54

HenriChab

513
1
3
10

Print random integer and phrase in same line?

2 Answers2