How to capture second match from the given text using regex

Question

I tried to capture the second match from given text i.e,

hash=e1467eb30743fb0a180ed141a26c58f7&token=a62ef9cf-2b4e-4a99-9335-267b6224b991:IO:OPCA:117804471:OPI:false:en:opsdr:117804471&providerId=paytm

In the above text, I want to capture the second number with the length of 9 (117804471).

I tried following, but it didn't work; so please help me resolving in this.

`^(?:.*?\K\b[0-9]{9}\b)`? See https://regex101.com/r/YeDFCe/2 — Wiktor Stribiżew, Mar 16 '21 at 13:08
Sorry, forgot it should be the second occurrence, you need to add `{2}` at the end. — Wiktor Stribiżew, Mar 16 '21 at 13:48

score 0 · Answer 1 · answered Mar 16 '21 at 13:46

You can use

^(?:.*?\K\b[0-9]{9}\b){2}

Details:

^ - start of string
(?: - start of a non-capturing group:
- .*? - any zero or more chars other than line break chars (as few as possible) followed with
- \K - match reset operator discarding text matched so far
- \b[0-9]{9}\b - a 9-digit number as a whole word
){2} - two occurrences of the pattern sequence defined above.

1 Answers1