Python case insensitive or sensitive strings as input

Question

I have the following script:

ip = input('Enter your string: ')
if 'tree' in ip:
   print('Correct string')

I would like to print 'Correct string' even if the user input is 'TREE' or 'tree' based on the case. How do I do that (optimally rather than using else or elif)?

If the input from the user is 'TREE' then the script should give an output:

CORRECT STRING

If the input from the user is 'tree' then the script should give an output:

correct string

How do I do that?

Side note: If you use the ``in`` operator, it will also match ``street`` for example, because ``street`` contains ``tree``. — Mike Scotty, Mar 16 '21 at 14:05
you can't do that without an `if-else`. and what if user inputs `tREe`, `trEE`, `TrEE`? — Krishna Chaurasia, Mar 16 '21 at 14:08

score 1 · Answer 1 · answered Mar 16 '21 at 14:03

1

Convert the user input to lower case as:

ip = input('Enter your string: ').lower()
if 'tree' in ip:
   print('Correct string')

answered Mar 16 '21 at 14:03

Krishna Chaurasia

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Python case insensitive or sensitive strings as input

1 Answers1