How do I create a vector with an increment step?

Question

How do I generate a vector with a specified increment step (e.g. 2)? For example, how do I produce the following

1,3,5,7,9,11,13,15,17,19

I want to do it with the function 1:19 with the jump of 2.

I know the seq function, I want to know if there is a way to create the vector in this way 1:19(with jumps of 2) ?

Thanks for the answer, i know the seq function. i want to know if there is a way to create the vector in this way 1:19(with jumps of 2) — Yoav Scheinfeld, Mar 22 '21 at 12:30
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Since yo know the `seq` function, you should know that it contains a `by` argument, which does exactly what you want. — desertnaut, Mar 22 '21 at 12:58
Possible duplicate of "extract every nth" https://stackoverflow.com/q/5237557/680068 — zx8754, Mar 22 '21 at 13:04

score 3 · Answer 1 · edited Mar 22 '21 at 12:57

3

Use seq (type ?seq into the R console for details):

vec = seq(1, 19, 2)

where from = 1, to = 19, by = 2.

edited Mar 22 '21 at 12:57

desertnaut

answered Mar 22 '21 at 12:35

trevelyan

1

`seq` is the most natural and direct way to generate an incremental vector. – SteveM Mar 22 '21 at 12:47

score 3 · Accepted Answer · edited Mar 22 '21 at 12:54

3

You can use a logical vector (length 2 but which will be recycled) to subset 1:19:

(1:19)[c(TRUE, FALSE)]
# [1]  1  3  5  7  9 11 13 15 17 19

edited Mar 22 '21 at 12:54

s_baldur

answered Mar 22 '21 at 12:39

Cath

2 Answers2