sizeof Calloc producing wrong output

Asked Mar 26 '21 at 17:27

Active Mar 26 '21 at 17:27

Viewed 68 times

I created a calloc object :

char* i2s_read_buff = (char*) calloc(1024*16, sizeof(char));

What I understood from the definition of calloc is that it will create array of 1024*16 elements and each element will be 1 byte. So it should be a 1024*16/8 = 2048 bytes array.

But

sizeof(i2s_read_buff)

produces output 4. I was expecting 2048 as output.

Can someone explain what is going on here?

asked Mar 26 '21 at 17:27

Anudocs

2

You are getting the size of char * which is different fron the memory allocation done at the pointer – Antonin GAVREL Mar 26 '21 at 17:30
1

https://stackoverflow.com/questions/1281686/determine-size-of-dynamically-allocated-memory-in-c – Antonin GAVREL Mar 26 '21 at 17:31
@AntoninGAVREL isnt sizeof(char) is 1 always? – Anudocs Mar 26 '21 at 17:40
sizeof(char *) is different from sizeof(char): https://stackoverflow.com/questions/12353973/sizeof-char-array-in-c-c – Antonin GAVREL Mar 26 '21 at 17:49
I do not get the `/8` part of your calculation. It seems that you think the size of a `char` is one eigth of a byte. – Yunnosch Mar 26 '21 at 18:35

sizeof Calloc producing wrong output

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