sentinel error occurred while executing oct2py in python for running octave script

Question

I am trying to use oct2py to run octave script(.m file) in python. here is the code

import os 
os.environ['OCTAVE_EXECUTABLE'] = ('C:\\Program Files\\GNU Octave\\Octave-6.2.0\\mingw64\\bin\\octave-cli.exe')
import oct2py
out = oct2py.Oct2Py()
out.source('main.m')

it runs my .m file and shows the results also but after that I receive following error.

error: 'sentinel' undefined near line 99, column 99
error: called from
    _pyeval at line 99 column 10

whats going wrong here?

did you manage to solve this? I am having the same problem. – philbox2 Apr 27 '21 at 10:35 — philbox2, Apr 27 '21 at 10:35

score 1 · Answer 1 · answered Apr 27 '21 at 10:45

1

I was having the same issue. It was resolved when I got rid of all clear all and close statements. Although I suspect clear to be the culprit.

This seems to be a known problem https://github.com/blink1073/oct2py/issues/185, which is your own post. Ah well ;)

answered Apr 27 '21 at 10:45

philbox2

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Sorry, I just forgot to close this thread here, Yes "clear" is the real culprit. xd – Karan Sohal Apr 29 '21 at 12:49

score 0 · Answer 2 · answered Apr 29 '21 at 12:51

0

https://github.com/blink1073/oct2py/issues/185 Here is the link regarding this thread. It's all due to "clear".

answered Apr 29 '21 at 12:51

Karan Sohal

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This is rather a comment than an answer. – Robson Apr 29 '21 at 13:25

sentinel error occurred while executing oct2py in python for running octave script

2 Answers2