I'm trying to write an expression parser. One part I'm stuck on is breaking down an expression into blocks via its appropriate order of precedence.
I found the order of precedence for C++ operators here. But where exactly do I split the expression based on this?
I have to assume the worst of the user. Here's a really messy over-exaggerated test example:
if (test(s[4]) < 4 && b + 3 < r && a!=b && ((c | e) == (g | e)) ||
r % 7 < 4 * givemeanobj(a & c & e, b, hello(c)).method())
Perhaps it doesn't even evaluate, and if it doesn't I still need to break it down to determine that.
It should break down into blocks of singles and pairs connected by operators. Essentially it breaks down into a tree-structure where the branches are the groupings, and each node has two branches.
Following the order of precedence the first thing to do would be to evaluate the givemeanobj()
, however that's an easy one to see. The next would be the multiplication sign. Does that split everything before the *
into a separate , or just the 4
? 4 * givemeanobj
comes before the <
, right? So that's the first grouping?
Is there a straightforward rule to follow for this?