Get just the filename from a file path stored as a string

Question

How can I remove the path and leave only the filename and extension inside a variable?

root=tk.Tk()
root.withdraw()
FileName=filedialog.askopenfilenames()
print(Filename)

I want only for example namefile.txt and not the whole path, like /path/to/namefile.txt.

Have a look at `os.path.basename()` – John Gordon Mar 27 '21 at 23:48 — John Gordon, Mar 27 '21 at 23:48

score 8 · Accepted Answer · answered Mar 27 '21 at 23:44

8

For python3.4+, pathlib

from pathlib import Path

name = Path(Filename).name

answered Mar 27 '21 at 23:44

kennyvh

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TypeError: expected str, bytes or os.PathLike object, not tuple – Mar 27 '21 at 23:50
@andreealombardo in your code, you use `askopenfilenames()`, which returns a tuple. Try `Path(Filename[0]).name` – kennyvh Mar 27 '21 at 23:52
1

It's worth pointing out, I think, that this works on any platform. Pretty much any method other than this requires manually mucking about with different path separators on Windows vs. Mac/Linux, and ain't nobody got time for that. – CrazyChucky Mar 28 '21 at 00:05

score 0 · Answer 2 · answered Mar 27 '21 at 23:45

First, you need to sanitize the string so it works cross-platform, then you can just pull the last section.

filename = filename.replace('\\', '/') # Turns the Windows filepath format to the Literally everything else format.
filename = filename.split('/')[-1]

Get just the filename from a file path stored as a string

2 Answers2