How can I remove the duplicated ID's from a list

Question

Lets say I have a list with integers.

lst = [1,2,3,3,2,1]

When I want to print ID's of all elements in the list i'm getting duplicated ID's. How can I prevent it?

Example :

It would be better to post your example code as a text inside `code`, not as a screenshot. — Kostas, Mar 30 '21 at 16:38
I just wanted to show the output but thanks for the warning. I will be more careful next time. — roxz, Mar 30 '21 at 16:42
Please add code and data as text ([using code formatting](//stackoverflow.com/editing-help#code)), not images. Images: A) don't allow us to copy-&-paste the code/errors/data for testing; B) don't permit searching based on the code/error/data contents; and [many more reasons](//meta.stackoverflow.com/a/285557). Images should only be used, in addition to text in code format, if having the image adds something significant that is not conveyed by just the text code/error/data. — Machavity, Mar 31 '21 at 17:26

score 2 · Answer 1 · answered Mar 30 '21 at 16:42

2

for i in set(lst):
    print(id(i))

Since sets cannot contain duplicate values

answered Mar 30 '21 at 16:42

TruVortex_07

score 0 · Answer 2 · answered Mar 30 '21 at 16:34

0

for i in range(len(lst)):
    if lst[i] not in lst[:i]:
        print(id(lst[i]))

answered Mar 30 '21 at 16:34

Kostas

score 0 · Answer 3 · answered Mar 30 '21 at 17:20

from collections import OrderedDict
lst = [1,2,3,3,2,1]
for i in list(OrderedDict.fromkeys(lst)):
    print(id(i))

If you don't care about the order, use this function:

l = [1,2,3,3,2,1]
def remove_duplicates(l):
    return list(set(l))

for i in remove_duplicates(l) :
    print(id(l))

3 Answers3