Print out just filename from bash array

Question

I have an array and loop printing out the filename+extension, but i just want to print the filename. How can I do that?

tffilearray=(`find ./ -maxdepth 1 -name "*.json"`)
for filepath in "${tffilearray[@]}"; do
    echo $filepath
done

Btw.: I suggest to remove first line and replace `for filepath in "${tffilearray[@]}"; do` with `for filepath in *.json; do`. — Cyrus, Apr 02 '21 at 14:41

score 0 · Answer 1 · answered Apr 02 '21 at 14:32

0

Got it!

for filepath in "${tffilearray[@]}"; do  basename $filepath .json; done

answered Apr 02 '21 at 14:32

Jshee

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Please mark the question as duplicate since your answer is already mentioned in the proposed duplcate. – 0stone0 Apr 02 '21 at 14:42

score 0 · Answer 2 · answered Apr 02 '21 at 17:44

As Cyrus pointed out, using a shell wildcard is cleaner than find (since you don't need to search multiple directories or apply a complex search rule); also, you can apply the shell pattern rule (from the duplicate question) to the entire array at once:

tffilearray=(*.json)    # Get all the *full* filenames
tffilearray=("${tffilearray[@]%.*}")    # Trim off the extensions

[I'm marking this Community Wiki to avoid points on a mostly-duplicate question.]

Print out just filename from bash array

2 Answers2