In Android 10, Picasso is able to truly display an image with the Uri of the image without any permission but openInputStream requires permission

Question

In an Android application,
And Android 10 regarding Scoped Storage,

Picasso is able to truly display an image with the Uri of an image
And it does not require any permission even if the versin of Android is 10
But when I try to use openInputStream, an error occurs which indicates permission is not granted

I wonder how Picasso can display the image without any permission but opening stream requires permission

The code is as following:

        Picasso.with(mContext).load(mUri).resize(200, 200).into(mImageButton);

        InputStream mInputStream;
        try
        {
            mInputStream = mContext.getContentResolver().openInputStream(mUri);
        } catch (Exception e) {
            e.printStackTrace();
        }

And the error is as following:

java.lang.SecurityException: Permission Denial: reading com.miui.gallery.provider.GalleryOpenProvider uri content://com.miui.gallery.open/raw/storage/emulated/0/Download/MellatMobileBank_Android.apk/icons/jar-gray.png from pid=2300, uid=10251 requires the provider be exported, or grantUriPermission()

Then, how can I have the stream of the image without granting permission?

Edit:
I did a test in onActivityResult where the image result could be retrieved from to see if the openInputStream works there or not
The code is as following:

@Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == Constants.Uri_M) {
                if (resultCode == RESULT_OK) {
                    Uri_M = data.getData();
                    Uri_M_String = Uri_M.toString();

                    mInputStream = getApplicationContext().getContentResolver().openInputStream(Uri_M);

Above code works fine while the following code has the same previous error (permission issue):

@Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == Constants.Uri_M) {
                if (resultCode == RESULT_OK) {
                    Uri_M = data.getData();
                    Uri_M_String = Uri_M.toString();

                
                    Uri b = Uri.parse(Uri.decode(Uri_M_String));
                    mInputStream = getApplicationContext().getContentResolver().openInputStream(b);

The point is Picasso is working fine with Uri_M_String but for openInputStream I first convert the Uri_M_String to Uri_M as following:

Uri Uri_M = Uri.parse(Uri.decode(Uri_M_String));

And then:

mInputStream = getApplicationContext().getContentResolver().openInputStream(Uri_M);

Which results in the error
So the problem is the conversion I'm doing to get the Uri from Uri string

But how can I reach the true Uri from its Uri string?

Where is the File referred by "mUri" located in the file system? — Demonick, Apr 05 '21 at 07:49
Then you could probably use Environment.DIRECTORY_PICTURES, as shown here: https://stackoverflow.com/a/10811776/313870 — Demonick, Apr 05 '21 at 07:53
Please start telling how you obtained that uri. After that tell at which moment you use Picasso or try to open an InputStream. — blackapps, Apr 05 '21 at 08:27
Uri.decode is creating the problem and without it there is no problem, I should find a workaround for Uri.decode — AndroidPlayer2, Apr 05 '21 at 12:21

In Android 10, Picasso is able to truly display an image with the Uri of the image without any permission but openInputStream requires permission

0 Answers0