How do I plot a polygon from a list of tuples using Shapely package

Question

I tried it but I keep getting an error. Below is the code I use to plot:

from shapely.geometry import Polygon
import matplotlib.pyplot as plt


polygon1 = Polygon([(0,5),
                    (1,1),
                    (3,0),
                    ])

plt.plot(polygon1)
plt.show()

However, I keep getting a TypeError: float() argument must be a string or a number, not 'Polygon' when calling plt.plot(polygon1).

Does this answer your question? [How do I plot Shapely polygons and objects using Matplotlib?](https://stackoverflow.com/questions/55522395/how-do-i-plot-shapely-polygons-and-objects-using-matplotlib) — Georgy, Apr 06 '21 at 08:30
Interestingly enough, the code in the question is the exact copy of the code from the duplicate question. — Georgy, Apr 06 '21 at 08:32

score 1 · Accepted Answer · answered Apr 06 '21 at 04:01

1

Matplotlib cannot understand Polygon, you need to pass the polygon vertices in matplotlib plot.

Below code works:

from shapely.geometry import Polygon
import matplotlib.pyplot as plt

polygon1 = Polygon([(0,5),
                    (1,1),
                    (3,0)])

x,y = polygon1.exterior.xy
plt.plot(x,y)

answered Apr 06 '21 at 04:01

nimrobotics

114
1
8

Also, consider copy-pasting the error instead of adding a screen shot. – nimrobotics Apr 06 '21 at 04:03
It worked. I get it now. The plot function expects (x,y) parameters – kojo justine Apr 06 '21 at 09:07

How do I plot a polygon from a list of tuples using Shapely package

1 Answers1