How do I add a php variable to this jquery url setting?

Question

I'm trying to make the URL in the following example contain a php variable like this:

http://api.crunchbase.com/v/1/company/$company.js

This is my jquery code:

$.ajax({
url: "http://api.crunchbase.com/v/1/company/airbnb.js",
dataType: 'jsonp',
success: function(results){
    var number_of_employees = results.number_of_employees;
        }

What do I need to do to achieve this?

Thanks!

you can refer this question also-http://stackoverflow.com/questions/1616231/php-combining-url-with-variable — Vivek, Jul 15 '11 at 08:26

score 3 · Accepted Answer · answered Jul 15 '11 at 08:23

You'll need to output the variable as JavaScript from PHP at some point in the script. This can be done quite easily using json_encode:

var company = <?php echo json_encode($company) ?>;

Note that this will have to be placed in a file that is actually executed by PHP, rather than an inert .js file. One way to achieve this is to put it in an inline <script> in the HTML in your PHP template; e.g.

<script type="text/javascript">
    var company = <?php echo json_encode($company) ?>;
</script>

Ben Everard · Answer 2 · 2011-07-15T08:29:42.617

1

Try this:

<script type="text/javascript">
    var company = <?php echo json_encode($company); ?>;
    alert(company);
</script>

You're setting the company variable with the output of $company, you can then use this variable however you please in JavaScript.

$.ajax({
url: "http://api.crunchbase.com/v/1/company/" + company + ".js",
dataType: 'jsonp',
success: function(results){
    var number_of_employees = results.number_of_employees;
}

edited Jul 15 '11 at 08:29

answered Jul 15 '11 at 08:23

Ben Everard

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Parentheses missing and a string containing `"` or `\` at the end will break things... – ThiefMaster Jul 15 '11 at 08:25

score 0 · Answer 3 · edited Nov 06 '11 at 12:21

0

Can you try this, assuming you have the company name in the php $company variable:

$.ajax({
url: "http://api.crunchbase.com/v/1/company/<?php echo $company ?>.js",
dataType: 'jsonp',
success: function(results){
    var number_of_employees = results.number_of_employees;
}

edited Nov 06 '11 at 12:21

Bill the Lizard

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answered Jul 15 '11 at 08:26

Fabrizio D'Ammassa

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How do I add a php variable to this jquery url setting?

3 Answers3