Why it is showing 'Error' instead of 'Good'?

Question

I want to create a simple program which asks user the square of random number, and if the user inputs correct answer then it will show 'Good". But as you can see here, it is showing 'Error'. Why?

My code:

import random
a = random.randint(2, 10)
print(a)
b = a * a
print(b)
num = input("Enter answer\n")
if num == b:
    print("Good")
else:
    print("Error")

Please, post the code as a formatted snippet, do not link to the images. — Alexandr Tatarinov, Apr 11 '21 at 14:25
Input give the user input as a string, just use if int(num) == b: — Kumar Shivam Ray, Apr 11 '21 at 14:26
Perhaps [this](https://stackoverflow.com/q/20449427/2166798) will answer your question? — pjs, Apr 11 '21 at 20:26

score 1 · Answer 1 · answered Apr 12 '21 at 11:07

As @KumarShivamRay explained you :

Input give the user input as a string, just use if int(num) == b:

here modified code explaining it:

import random
a = random.randint(2, 10)
print(a)
b = a * a
print(b)
num = (input("Enter answer\n"))
print('type num :',type(num))
num = int(input("Enter answer\n"))  ### here you need to convert input to int type
print('type num :',type(num))
if num == b:
    print("Good")
else:
    print("Error")

Why it is showing 'Error' instead of 'Good'?

1 Answers1