RegEx to find all matches, not just one

Question

I'm looking for a RegEx expression that lets me find all instances that match a pattern.

PowerShell:

> if ("123 234 345 567" -match ".*(\d{3}).*") { $Matches | fl}

Name  : 1
Value : 567

Name  : 0
Value : 123 234 345 567

I'd like to also get the other three-digit values as individual matches.

-S

What needs to be your results with for example "123 4567890"? Would you want something like [here](https://regex101.com/r/hyLImW/1)? — JvdV, Apr 14 '21 at 09:46
@JvdV - I only expect specific-length values, so at this point I only need to concern myself with getting multiple matches. — Sigurd Garshol, Apr 14 '21 at 10:10
Since it worked, please consider accepting the answer. If you have any doubts, please feel free to drop a comment below the answer. — Wiktor Stribiżew, Apr 14 '21 at 14:27

Wiktor Stribiżew · Accepted Answer · 2021-04-14T10:19:43.147

You can use

$s = "123 234 345 567"
Select-String '\d{3}' -input $string -AllMatches | % {$_.matches.value}

See demo:

Notes:

The pattern can also be defined in other ways:

(?<!\d)\d{3}(?!\d) pattern lets you extract three consecutive digits that are not enclosd with other digits
(?<!\d\.?)\d{3}(?!\.?\d) - to match only integer numbers consisting of 3 digits in messed-up contexts
(?<!\S)\d{3}(?!\S) - match three digit chunks in between whitespaces or start/end of string
\b\d{3}\b - match three digit numbers as whole words (not enclosed with letters, digits or underscores).

1 Answers1