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I want to call my python script runner.py from Scala program, I doing it like this:

runner.py:

print("testing")

`program.scala:

val res = "python3 runner.py" !

The problem is that this only return 0, but not the printed output. How can I get that in Scala?

bad_coder
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user15609698
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  • To run external programs, you can use methods from the package scala.sys.process https://www.scala-lang.org/api/current/scala/sys/process/index.html – KosWarm Apr 19 '21 at 15:55
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    Does this contain enough material to either answer your question, or at least formulate more precisely what the problem is? https://stackoverflow.com/questions/15411728/scala-process-capture-standard-out-and-exit-code In particular, [this here](https://stackoverflow.com/a/15438493/2707792) shows how to capture everything. – Andrey Tyukin Apr 19 '21 at 16:17

1 Answers1

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As explained in the ScalaDocs, ! returns the process exit code. !! returns the process StdOut. If you need both you'll want to add a ProcessLogger.

jwvh
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