Finding a Javascript structure in an array based on one field

Question

I am pushing a structure to an array which looks like the following

arr.push( {age: 32, name: "Joe"} );
arr.push( {age: 93, name: "Mike"} );
arr.push( {age: 19, name: "Billy"} );

What I would like to do is just find out if "Mike" is in the array. Something like:

arr.includes({name: "Mike"})

I know this doesn't work but it shows what I'm looking for.

You're looking for `.find()` or `.findIndex()` – Pointy Apr 19 '21 at 17:49 — Pointy, Apr 19 '21 at 17:49
`arr.some(el => el.name === 'Mike')` – CherryDT Apr 19 '21 at 17:50 — CherryDT, Apr 19 '21 at 17:50

score 2 · Answer 1 · answered Apr 19 '21 at 17:50

2

you can use find in following way to get the targeted node from array of objects

let result = array.find(t=>t.name=='Mike')

answered Apr 19 '21 at 17:50

Jatin Parmar

Since the question was just whether it exists and not to get a reference to it, `some` will suffice though. – CherryDT Apr 19 '21 at 17:52
1

Awesome. Thanks. Can't you tell I'm a C programmer :) – jiveturkey Apr 19 '21 at 17:54

1 Answers1