I want to print digit value but its not working

Question

I want to print 157.30 but print 15730

The code is

String Printprice="$157.30";
double value = Integer.parseInt(Printprice.replaceAll("[^0-9]",""));

Output: 15730

Answer 1

First problem

Printprice.replaceAll("[^0-9]","") removes everything that is not a digit, also the decimal point.

If you want to keep the decimal point, you need to change the regex to [^0-9.] (note the . after the 0-9):

Second problem

Furthermore, Integer.parseInt parses an int, not a double. If you want a double, you should use Double.parseDouble instead:

double value = Double.parseDouble(Printprice.replaceAll("[^0-9.]",""));

Other approach

If you just want everything after the first character, you can use String#substring in order to remove the first character:

double value = Double.parseDouble(Printprice.substring(1));

Things woth noting

It shoud also be noted that variables should be camelCase by convention. Instead of Printprice, you should use printPrice:

String printPrice="$157.30";
double value = Double.parseDouble(printPrice.substring(1));

Yet another thing worth noting is that you shouldn't use IEEE floating point numbers for currency calculations as those are a bit weird. Instead, you may want to save the price in cents (as a long value) or use NumberFormat/Currency as suggested by Achintya Jha.

Answer 2

Try using NumberFormat class https://docs.oracle.com/javase/8/docs/api/java/text/NumberFormat.html

NumberFormat numberformat = NumberFormat.getCurrencyInstance();
Number number = null;
try {
        number = numberformat.parse("$157.30");
    } catch (ParseException e) {
        e.printStackTrace();
    }
System.out.println(number.toString());

Answer 3

String price ="$157.30";
float value = Float.parseFloat(price.replace("$",""));
System.out.println(value);