Checking if a list of YouTube videos still online with Python

Question

I'm trying to check if a list of 4 YouTube videos still online. I know one of them is offline, and from time to time I want to see if any action was made upon the others. Searching through the web and with a little coding (I'm a beginner) I made this:

import requests
from pprint import pprint

videos = ["id1","id2","id3","id4"]

for i in videos:
    id_of_video = i
    your_api_key = 'myapi' 
    url = 'https://www.googleapis.com/youtube/v3/videos?id={}&key={}&part=status'.format(id_of_video, your_api_key)
    url_get = requests.get(url)
    pprint(url_get.json())

The code runs well and I receive something like this (I copied just two results):

{'etag': 'somenumbersandcharactershere',
 'items': [{'etag': 'somenumbersandcharactershere',
            'id': 'videoid',
            'kind': 'youtube#video',
            'status': {'embeddable': True,
                       'license': 'youtube',
                       'madeForKids': False,
                       'privacyStatus': 'public',
                       'publicStatsViewable': True,
                       'uploadStatus': 'processed'}}],
 'kind': 'youtube#videoListResponse',
 'pageInfo': {'resultsPerPage': 1, 'totalResults': 1}}

{'etag': 'somenumbersandcharactershere',
 'items': [],
 'kind': 'youtube#videoListResponse',
 'pageInfo': {'resultsPerPage': 0, 'totalResults': 0}}

One of them is online and the other one is not. Great.

But I want to create a code that check it for me from time to time and says: "This video ID is not available anymore". But I don't know how.

My main task right now is to print a message for each video ID! So, let's say: "ID1 is on-line" and "ID2 is offline".

I thought about creating an if statement to check the results of the "url_get.json()" tag but it only holds the last video ID...

If I run

url_get.json()

I get only the last ID from the list.

So, you want to `print` a `'message'`, only `if` the value of `your_json['pageInfo']['totalResult']` is `== 0`? — Grismar, Apr 21 '21 at 23:21
you can create a cron job for this or create a bot that will do this for you — sahasrara62, Apr 21 '21 at 23:24
https://stackoverflow.com/questions/11774925/how-to-run-a-python-file-using-cron-jobs — sahasrara62, Apr 21 '21 at 23:26
@Grismar yes. Actually, I want to print a message for each video ID! So, let's say: "ID1 is on-line" and "ID2 is offline". — interferemadly, Apr 21 '21 at 23:27

KetZoomer · Accepted Answer · 2021-04-22T00:26:24.060

1

You could use a dictionary for this. At first, I set the values to None. Then, when looping through the dictionary, I set the values to the returned JSON. At the end of the program, I print IDx is offline or online. You can do whatever you want with the data in the dictionary though.

import requests
from pprint import pprint

videos = {"id1": None, "id2": None, "id3": None, "id4": None}
for i in videos:
    id_of_video = i
    your_api_key = 'myapi' 
    url = 'https://www.googleapis.com/youtube/v3/videos?id={}&key={}&part=status'.format(id_of_video, your_api_key)
    url_get = requests.get(url)
    pprint(url_get.json())
    videos[i] = url_get.json()

for video in videos:
    if videos[video]["pageInfo"]["resultsPerPage"] == 0:
        print(f"{video.upper()} is offline")
    else:
        print(f"{video.upper()} is online")

edited Apr 22 '21 at 00:26

answered Apr 21 '21 at 23:42

KetZoomer

2,701
3
15
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@interferemadly, if this answered your question, please click the checkmark – KetZoomer Apr 21 '21 at 23:47
Tried this, but received this error: `TypeError Traceback (most recent call last) in 12 13 for video in videos: ---> 14 if video[videos]["pageInfo"]["resultsPerPage"] == 0: 15 print(f"{video.upper()} is offline") 16 else: TypeError: string indices must be integers` – interferemadly Apr 21 '21 at 23:54
@interferemadly fixed :) – KetZoomer Apr 21 '21 at 23:57
hey man, I don't know if I'm missing something – as I said, I'm a beginner. Still getting and error: `TypeError Traceback (most recent call last) in 11 12 for video in videos: ---> 13 if videos[video]["pageInfo"]["resultsPerPage"] == 0: 14 print(f"{video.upper()} is offline") 15 else: TypeError: 'Response' object is not subscriptable` – interferemadly Apr 22 '21 at 00:18
now it should be fixed, I forgot to turn it into a json – KetZoomer Apr 22 '21 at 00:26
Thanks, @KetZoomer. It worked. I will read the core carefully to understand better :) – interferemadly Apr 22 '21 at 01:13

score 0 · Answer 2 · answered Apr 21 '21 at 23:24

0

So you want to write a program that periodically pings Youtube. The easiest way to achieve it would be something like

from time import sleep

delay : int = 20

while True:
# ping YT here
  sleep(delay)

This will run it every 20 seconds. There are a number of problems here.

It runs forever
The only way to stop program is by clicking Ctrl+C
It also won't be exactly 20 seconds

But it will do the trick at first. I found great question (thread???) here at stackOverflow The Answer proposes to use some more advanced concept of "event loop". It's definitely worth getting into if you have time.

answered Apr 21 '21 at 23:24

CartesianCoordinateSystem

94
2
5

1

if server fails or system is shutdown then this won't work, program need to run again. better to create a cron job for this job – sahasrara62 Apr 21 '21 at 23:27
Thanks, this is part of the problem. But my main question is: how to check each ID and print a message for each one! So, let's say: "ID1 is on-line" and "ID2 is offline". – interferemadly Apr 21 '21 at 23:28
@CartesianCoordianateSystem, please read the question fully before answering – KetZoomer Apr 21 '21 at 23:58

Checking if a list of YouTube videos still online with Python

2 Answers2