Array character as parameters in c

Asked Apr 22 '21 at 12:50

Active Apr 22 '21 at 13:18

Viewed 56 times

I have a problem with one thing, it works to compare a character in another function if I send it like '(' instead of an array character. Not the clearest description but look at the example code and you might understand.

char arr[5];
arr[0] = ")";

void func(){
  to_another_func("(");      
  to_another_func(&arr[0]);      
 }

void to_another_func(char*a) {
if(strcmp(a, "(") == 0)
printf("a is (");
}

According to me that's the same, if not, how can I make it the same?

edited Apr 22 '21 at 13:18

asked Apr 22 '21 at 12:50

Adam Röhr

2

What is the prototype for `to_another_func()`? – Fred Larson Apr 22 '21 at 12:51
3

`to_another_func(arr[0]);`? – MikeCAT Apr 22 '21 at 12:51
1

`to_another_func(&arr[0])` should compile at least with a warning. Anyway show a [mcve] – Jabberwocky Apr 22 '21 at 12:53
Oh its void to_another_func(char* a) – Adam Röhr Apr 22 '21 at 12:57
1

@AdamRöhr all clarifications should be _in the question_. You can [edit] your question and improve it. – Jabberwocky Apr 22 '21 at 12:58
yeah so it is not exactly the same, because you use one opened bracket and one closed bracket, but it doesn't matter if you pass a character or a character variable. – Bananenkönig Apr 22 '21 at 13:00
2

`'('` is an int. `&arr[0]` is a pointer to char. – William Pursell Apr 22 '21 at 13:14
The problem is that the code above doesn't work, it doesn't work to strcmp when a is arr[0] – Adam Röhr Apr 22 '21 at 13:15
1

I think you are looking for `to_another_func("(");` – William Pursell Apr 22 '21 at 13:15
@williampursell but '(' works and not &arr[0] – Adam Röhr Apr 22 '21 at 13:16
Undefined behavior often appears to work. Passing `'('` as the 2nd argument of `strcmp` is incorrect, since the parameter ought to be a `char *`, but you are passing an int. – William Pursell Apr 22 '21 at 13:17
But the thing is "(" works but not when I use &arr[0] – Adam Röhr Apr 22 '21 at 13:18
2

That's because `arr[0] = ")"` is wrong. You either want `char arr[5] = "(";` or `char arr[5]; arr[0] = '('; arr[1] = '\0';` – William Pursell Apr 22 '21 at 13:21
1

Or perhaps `char arr[5] = { '(', '\0' };` I think you are confused about the difference between `"("` and `'('`. – William Pursell Apr 22 '21 at 13:23
**ALWAYS READ COMPILER WARNINGS** `warning: assignment to 'char' from 'char *' makes integer from pointer without a cast [-Wint-conversion] 5 | arr[0] = ")";` – 0___________ Apr 22 '21 at 14:01

Array character as parameters in c

0 Answers0