Use 'in' to check is a word is part of an item in a list

Question

my code as follows:

a_list = ['apple', 'orange', 'banana', 'this is a dog']

print('apple' in a_list)
-->>True

print('dog' in item for item in a_list)
-->><generator object <genexpr> at 0x000001E870D13F90>

Question: Why do I get the <generator object at 0x000001E870D13F90>?

How can I check, if 'dog' is in any item of this list, and the position of this item, i.e., 'dog' is in the a_list[3]?

Thanks!

As to "Why do I get the generator", see https://stackoverflow.com/questions/5164642/python-print-a-generator-expression . — msanford, Apr 22 '21 at 18:53

score 3 · Accepted Answer · answered Apr 22 '21 at 18:53

3

You can use enumerate to get index and item at once.

for index, value in enumerate(a_list):
    if "dog" in value:
        print(index)

answered Apr 22 '21 at 18:53

Nikhil Patil

173
1
7

^ This is the most efficient answer to me – JD2775 Apr 22 '21 at 18:55

Harsheen Rajpal · Answer 2 · 2021-04-22T19:19:19.420

2

Using the predefined list , and a standard for loop, this should give you your expected answer:

a_list = ['apple', 'orange', 'banana', 'this is a dog']
for i in a_list:
    if "dog" in i:
         print(a_list.index(i))

edited Apr 22 '21 at 19:19

answered Apr 22 '21 at 18:50

Harsheen Rajpal

181
11

score 1 · Answer 3 · answered Apr 22 '21 at 18:43

1

You could use any, which checks through an iterator and returns True if any of them are try, else False (contrast with all which is only True if they are all True).

print(any('dog' in item for item in a_list))

answered Apr 22 '21 at 18:43

Adam Smith

52,157
12
73
112

thanks, but is there is any possibility to get the id of the item which includes the 'dog'? – Nina Apr 22 '21 at 18:45
@Nina the `id` or the index in the list? – Adam Smith Apr 22 '21 at 18:45
for example, 'dog' is in the a_list[3] – Nina Apr 22 '21 at 18:47

Use 'in' to check is a word is part of an item in a list

3 Answers3