Parsing date string to int using cpp

Question

I was trying to solve a problem. The Problem is : There is given a date string like 21/9/2013. I have to convert this date into int. I have used stoi but it is just showed first two int 21.

What is the int supposed to represent ? Eg what int value would you want to produce given your example date? — Jeremy Friesner, Apr 23 '21 at 04:07
What exactly are you supposed to return? As Jeremy said, 21 9 2013 is three ints, not one int. C++ doesn't let you return 3 ints. Do you want to return a string of these three ints? An array of 3 ints? Do you want to print 21 9 2013 to the console? — jdabtieu, Apr 23 '21 at 04:12

score 1 · Answer 1 · answered Apr 23 '21 at 04:16

What you want to do here is tokenize the string into three different substrings ("21", "9", and "2013"); then you can call stoi() on each substring and print out the integer stoi() returned for each one.

There are various ways to tokenize a string in C++; rather than choose one to repeat here, I'll just link to the StackOverflow question and answers on that topic.

score 1 · Accepted Answer · answered Apr 23 '21 at 04:48

I want to print 21 9 2013 to the console

So you don't really need three integers. You need three strings.

With these includes:

#include <string>
#include <sstream>
using namespace std;

You can parse a string like this:

string date = "21/9/2013";

into its components, like this:

stringstream stream(date);
string s;
while (std::getline(stream, s, '/') {
    cout << s << " ";
}
cout << endl;

The above should print out: 21 9 2013

If you really want integers, the above shouldn't be too hard to modify. You can use stoi on each iteration of the while loop above.

Parsing date string to int using cpp

2 Answers2