Making a 2D character array table in C

Asked Apr 23 '21 at 13:33

Active Apr 23 '21 at 13:33

Viewed 26 times

#include <stdio.h>

int main (void){
  char board[3][3];
  printf("Enter X or O>");
  for(int i=0; i<3; i++){
    for(int j=0; j<3; j++){
        scanf("%c", &board[i][j]);
    }
  }
  printf("Board: ");
  for(int i=0; i<3; i++){
    for(int j=0; j<3; j++){
        printf(" %c", board[i][j]);
    }
    printf("\n");
  }
}
/*Expected output: 
   X O X 
   O X O 
   X O O 
Actual output: 

  Board:  X
 O

 X

 O
 O
*/

I'm trying to make a 3x3 tic tac toe board using 2D arrays in C. This code works fine for an Int array but doesn't work as expected using char. I only get to input 5 characters for some reason instead of the 3x3=9 and the output is also jumbled. How can I fix this?

asked Apr 23 '21 at 13:33

hade34

What is your input? – MikeCAT Apr 23 '21 at 13:34
1

@hade34 Use scanf(" %c", &board[i][j]); See the blank before the symbol % – Vlad from Moscow Apr 23 '21 at 13:34
[You can fix by fixing input](https://wandbox.org/permlink/bbtuAXI8gt5YUYdS). – MikeCAT Apr 23 '21 at 13:35
See https://stackoverflow.com/questions/5240789/scanf-leaves-the-new-line-char-in-the-buffer – Support Ukraine Apr 23 '21 at 13:43
1

Short answer: With `%c` you read 5 expected chars and 4 newlines. Add a space before `%c` to skip whitespaces – Support Ukraine Apr 23 '21 at 13:45
Or just type all 9 input characters on one line. – stark Apr 23 '21 at 13:54

Making a 2D character array table in C

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