I am trying to create a for loop like this:
list = [a, b, c, a_1, b_1, c_1]
for i in list:
if str(i).endswith(".0"):
i = int(i)
print(type(a))
This outputs:
<class 'float'>
This means that the for loop didn't define the entry into an integer. I checked if this works to make sure it was the for loop:
if str(i).endswith(".0"):
i = int(i)
Does anyone know why the for loop wouldn't define the variable the same as outside of the loop? Any help would be appreciated.
The reason a is not being edited is that i is first assigned to the same value as a, then i is assigned to a different value without modifying a. Python has no way to get references to variables so that they can be edited. One workaround is to use indirection: create an object with an attribute to store the value, then i will point to the same object as a, and modifying the attribute of the object modifies both a.value and i.value:
from dataclasses import dataclass
from typing import Any
@dataclass
class Box:
value : Any
# note that the values are constructed like `Box(0.2)`
a, b, c, a_1, b_1, c_1 = (Box(i/10) for i in range(6))
list = [a, b, c, a_1, b_1, c_1]
for i in list:
if str(i.value).endswith(".0"):
i.value = int(i.value)
print(type(a.value))
You cannot assign a value to floats object. What you are trying to do is:
# something like
# assume i = 5.0
# if str(i).endswith('.0'):
# i = int(i)
# if str(5.0).endswith('.0'):
# 5.0 = 5
# what you want
list_ = [a, b, c, a_1, b_1, c_1]
for index, value in enumerate(list_):
if str(value).endswith(".0"):
list_[index] = int(value)
a, *rest = list_
print(type(a))
Note: list is python keyword. Avoid overriding it.
list_ = [1.0, 2, 1, 5.0]
for index, value in enumerate(list_):
if str(value).endswith(".0"):
list_[index] = int(value)
a, *rest = list_
print(type(a))
# class 'int'>
