How do I display the names of all the subdirectories inside a directory, without using a loop in Python?

Question

I have tried os.listdir() but it shows all the files & directories. I've tried other solutions but they mostly require a loop and I am finding ways to do it without a loop.

Does this answer your question? [Getting a list of all subdirectories in the current directory](https://stackoverflow.com/questions/973473/getting-a-list-of-all-subdirectories-in-the-current-directory) — Amit Vikram Singh, Apr 24 '21 at 12:23
Why don't you want to use a loop? Why does "but it shows all the files & directories." not suit your needs? — Karl Knechtel, Apr 24 '21 at 12:32

score 1 · Answer 1 · answered Apr 24 '21 at 12:25

1

Use os.walk

import os
subdirs = next(os.walk('.'))[1]
print(subdirs)

answered Apr 24 '21 at 12:25

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score 0 · Answer 2 · answered Apr 24 '21 at 12:44

Works with me:

import os

os.mkdir('f')
os.mkdir(r'f/file1')
os.mkdir(r'f/file2')
os.mkdir(r'f/file3')

os.mkdir('f/file1/abc')
os.mkdir('f/file2/def')
os.mkdir('f/file3/ghi')

os.listdir('f')

OT:

['file2', 'file3', 'file1']

listdir with a file

os.listdir('f/file1')

OT:

['abc']

How do I display the names of all the subdirectories inside a directory, without using a loop in Python?

2 Answers2